[tex]\it \dfrac{3}{4} =0,75\\ \\ \\ \dfrac{3}{2} =1,5\\ \\ \\ \dfrac{5}{2} =2,5[/tex]
Acum, vom avea:
[tex]\it \dfrac{\ 0,75^{(5}}{1,5}+\dfrac{\ 2,5^{(5}}{1,5} =\dfrac{0,15}{0,3} +\dfrac{0,5}{0,3} =\dfrac{0,15+0,5}{0,3}=\dfrac{ ^{100)}0,65}{0,3}=\dfrac{\ 65^{(5}}{30} =\dfrac{13}{6}[/tex]