Răspuns :
d) (1+2+...+20):14
[tex](\frac{20(20+1)}{2} ):14\\\\=(\frac{20*21}{2}):14\\\\=\frac{420}{2}:14\\\\=210:14\\\\=15[/tex]
1²+2²
=1+4
=5
⇒(1+2+...+20):14>1²+2²
e) (6+6:6)⁶⁻⁶-6⁶⁻⁶
=(6+1)⁰-6⁰
=7⁰-6⁰
=1-1
=0
⇒(6+6:6)⁶⁻⁶-6⁶⁻⁶<6
d) (1+2+...+20):14
[tex](\frac{20(20+1)}{2} ):14\\\\=(\frac{20*21}{2}):14\\\\=\frac{420}{2}:14\\\\=210:14\\\\=15[/tex]
1²+2²
=1+4
=5
⇒(1+2+...+20):14>1²+2²
e) (6+6:6)⁶⁻⁶-6⁶⁻⁶
=(6+1)⁰-6⁰
=7⁰-6⁰
=1-1
=0
⇒(6+6:6)⁶⁻⁶-6⁶⁻⁶<6