Fie a,b-doua numere
a+b=56
a/3=b/4
a=3k
b=4k
3k+4k=56
7k=56
k=56:7
k=8
a=3×8
a=24
b=4×8
b=32
Fie x-primul nr si y-al doilea nr
[tex]\frac{x}{3}= \frac{y}{4} =>x=\frac{3y}{4}[/tex]
x+y=56
[tex]\frac{3y}{4}+y=56\\\\\frac{3y}{4}+ \frac{4y}{4}= \frac{224}{4}|*4\\\\3y+4y=224\\\\7y=224\\\\y=\frac{224}{7} \\\\y=32[/tex]
x+y=56
x+32=56
x=56-32
x=24