[tex]\it x<-2|_{\cdot(-1)} \Rightarrow -x>2|_{+10} \Rightarrow 10-x>12> 0 \Rightarrow |10-x| =10-x\ \ \ \ (1)\\ \\ x<-2|_{-4} \Rightarrow x-4< -6<0 \Rightarrow |x-4|=(-x+4)\ \ \ \ (2)\\ \\ |10-x|-|x-4|\ \stackrel{(1),(2)}{=}\ 10-x-(-x+4)=10-x+x-4=6[/tex]
