Răspuns :
[tex]\displaystyle\bf\\\frac{x}{y}=4\\\\\frac{x+y}{2x+y}=?\\\\\textbf{Simplificam fortat fractia cu y.}\\\\\frac{~~x+y^{(y}}{2x-y}=\frac{\dfrac{x+y}{y}}{\dfrac{2x-y}{y}}=\frac{\dfrac{x}{y}+\dfrac{y}{y}}{\dfrac{2x}{y}-\dfrac{y}{y}}=\frac{\dfrac{x}{y}+1}{2\cdot\dfrac{x}{y}-1}= \frac{4+1}{2\cdot4-1}=\boxed{\bf \frac{5}{7}}[/tex]
