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Af 5 nr rationale stiind ca primele trei sunt d.p. cu 5,6,10 si ultimele trei sunt d.p. cu 3,8,12 si suma lor este 200....repedeeee

Răspuns :

Triunghiul1

(a;b;c) d.p. (5;6;10) => a/5=b/6=c/10

(c;d;e) d.p. (3;8;12) => c/3=d/8=e/12

=>a=5c/10

=c/2

=>b=6c/10

=3c/5

=>d=8c/3

=>e=12c/3

=4c

a+b+c+d+e=200

c/2+3c/5+c/1+8c/3+4c/1=200/1

15c/30+18c/30+30c/30+80c/30+120c/30=6000/30

=>15c+18c+30c+80c+120c=6000

263c=6000

c=6000/263

a=6000:2/263=3000/363

b=6000/263 × 3/5 = 3600/263

d=6000/263 × 8/3 = 1600/263

e=6000/263 × 4 = 24000/263

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