Răspuns :
1. (x+2)(x+3)+(x-2)²-2x²=
=x²+3x+2x+6+x²-4x+4-2x²=x+10
2. √32-5√50+6√8=
=4√2-5×5√2+6×2√2=
=4√2-25√2+12√2=
= -21√2+12√2= -9√2
1. (x+2)(x+3)+(x-2)²-2x²=
=x²+3x+2x+6+x²-4x+4-2x²=x+10
2. √32-5√50+6√8=
=4√2-5×5√2+6×2√2=
=4√2-25√2+12√2=
= -21√2+12√2= -9√2