[tex](125^3:25^2:5-27^4:9^5+8^3:4^2:(2^2)^0):8=\\=((5^3)^3:(5^2)^2:5^1-(3^3)^4:(3^2)^5+(2^3)^3:(2^2)^2:1):8=\\=(5^9:5^4:5^1-3^{12}:3^{10}+2^9:2^4):8=\\=(5^{9-4-1}-3^{12-10}+2^{9-4}):8=\\=(5^4-3^2+2^5):8=(625-9+32):8=648:8=81[/tex]
Salutări din Rusia :^)
