Răspuns:
Explicație pas cu pas:
[tex]\dfrac{cos10*cos120*tg240}{sin10*cos60*ctg170} =\dfrac{cos10*cos(180-60)*tg(180+60)}{sin10*cos60*ctg(180-10)} =\\=\dfrac{cos10*(-cos60)*tg60}{sin10*cos60*(-ctg10)} =\dfrac{cos10*tg60}{sin10*ctg10} =\dfrac{cos10*tg60}{cos10}=tg60=\sqrt{3}[/tex]
Aplicate formule de reducere la cadranul I și sinα·ctgα=cosα