Răspuns:
Explicație:
254,545 * (100 - 12)/100 = 254,545 *88/100 = 224 g Fe pur
M Fe = 56 g/mol
n = 224/56 = 4 mol Fe
Fe + 2HCl = FeCl2 + H2
1 mol Fe..........2 mol HCl
4 mol Fe.........x
x = 4*2 = 8 mol HCl
M HCl = 36,5 g/mol
m = 8*36,5 = 292 g HCl
100 g solutie 20%...................20 g HCl
m sol..........................................292 g HCl
m sol = 292*100/20 = 1460 g