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suma a patru numere este 5 .Stind ca ele sunt invers proportionale cu numerele 1pe2, 1pe3,0,4 ,0,2 Aflati numerele repede

Răspuns :

StanciuGabriela29
a+b+c+d= 5
1/2 * a = 1/3 * b = 2/5 *c = 1/5 * d 
a/2 = b/3 = 2c/5 = d/5
a/2=d/5 => 5a= 2d => a = 2d/5
b/3 = d/5 => b = 3d/5
2c/5 = d/5 => 10c = 5d => c = d/2
2d/5+ 3d/5+d/2+d = 5
4d+6d+5d+10d = 50
25d= 50 => d = 2
a+b+c = 5-2 = 3
a/2=2c/5 => 5a=4c => a= 4c/5
b/3= 2c/5 => 6c/5
4c/5+6c/5+c = 3
2c+c = 3 => c= 1
a+b = 3-1 = 2
a/2=b/3 => 3a=2b => a = 2b/3
2b/3 + b = 2
2b+3b = 6 => 5b = 6 => b= 6/5
a= 4/5

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