Buna!
m∈R, m=?
[tex]f(x)=x^{2} -4mx+6m, -\frac{DELTA}{4a} =2\\a=1, b=-4m, c=6m\\DELTA=b^{2} -4ac=16m^{2} -24m=4(4m^{2} -6m)\\-\frac{DELTA}{4a} =2=>-\frac{4(4m^{2} -6m)}{4} =2=>-4m^{2}+6m=2=>\\-4m^{2}+6m-2=0\\a=-4,b=6,c=-2,DELTA=36-32=4\\m1=\frac{-b+\sqrt{DELTA} }{2a} =\frac{-6+2}{-8} =\frac{-4}{-8} =\frac{1}{2} \\m2=\frac{-6-2}{-8} =-1\\S=-1,\frac{1}{2}[/tex]
Bafta!
