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a fost răspuns

cum se rezolva 2,5+[1,2+0,(6)]*3/7=?
[1,(6)+2/3]*0,2+5/6=?

Răspuns :

0,(6)=6/9=2/32,5+[1,2+0,(6)]x3/7=25/10+(12/10+2/3)x3/7=
25/10+(36/30+20/30)x3/7=
25/10+56/30x3/7=
25/10+8/10=33/10=3,3

1,(6)=(16-1)/9=15/9=5/3
[1,(6)+2/3]x0,2+5/6=
(5/3+2/3)x2/10+5/6=
7/3x2/10+5/6=
14/30+5/6=
14/30+25/30=39/30=13/10=1,3

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