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Aflati numarul natural x din egalitatea 40+[(21-24:x):3+4]·2-10=44​

Răspuns :

Daria214682

40+[(21-24/x)×1/3+4]×2-10=44

40+[(21x-24)/x×1/3+4]×2-10=44

40+{[3(7x-8)]/x×1/3+4}×2-10=44

40+[(7x-8)/x+4]×2-10=44

40+[2(7x-8)]/x+8-10=44

40+(14×-16)/x+8-10=44

38+(14x-16)/×=44

(14x-16)/x=6

14x-16=6x

14x-6x=16

8x=16

x=2

Răspuns:

Explicație pas cu pas:

40+[(21-24:x):3+4]·2-10=44​

[(21-24:x):3+4]·2=44​ +10 - 40

[(21-24:x):3+4]·2=14     ( :2)

(21-24:x):3+4 =7

(21-24:x):3 =7 -4

(21-24:x):3 =3     (*3)

21-24:x =9

21 - 9 = 24 :x

12 = 24 : x     (*x)

12x = 24

x= 24 :12

x=2

succes !!

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