Răspuns :
1). ... 4x²-9=6x-4 ⇔ 4x²-6x-5=0 ⇒ Δ=36-4*4*(-5)=36+80=116 adica: √Δ=2√29
[tex]x_{1;2}=\frac{6\pm2\sqrt29}{8}\rightarrow\;x_{1;2}=\frac{3\pm\sqrt{29}}{4}[/tex];
2). ... 4x+8 = 4(x+2) ;
[tex]x_{1;2}=\frac{6\pm2\sqrt29}{8}\rightarrow\;x_{1;2}=\frac{3\pm\sqrt{29}}{4}[/tex];
2). ... 4x+8 = 4(x+2) ;