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a fost răspuns

Calculati :
a) 5[tex] \frac{1}{3} [/tex] : 6[tex] \frac{2}{5} [/tex]+ ( 12 : 3[tex] \frac{3}{5} [/tex] + 2[tex] \frac{2}{3} [/tex] ) x [tex] \frac{2}{3} [/tex]
b) [ [tex] \frac{16}{5} [/tex] - ( 1+[tex] \frac{1}{2} [/tex] )] : [tex] \frac{7}{20} [/tex]

Răspuns :

MFM
16/3x5/32+(12x5/18+8/3)x2/3=5/6+(10/3+8/3)x2/3=5/6+18/3x2/3=5/6+4=29/6 b) (16/5-3/2)x20/7=(32-15)/10x20/7=17/10x20/7=34/7=4intregi 6/7

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