Răspuns: glucoza are Fomula C6H12O6 se calculeaza M C6H12O6= 6.12+12+6.16=72+12+96=180g/mol se aplica regula de 3 simpla la 180 g glucoza........72g C..........12 gH..........96 g O 100g glucoza.............x..................y.....................z x=100.72/180=40%C y=100.12/180=6,66%H z=100.96/180=53,55%O
Explicație:
