[tex]x,(34)=\frac{\overline{x34}-x}{99}=\frac{100x+34-x}{99}=\frac{99x+34}{99}\;;\\
3,(4x)=\frac{\overline{34x}-3}{99}=\frac{340+x-3}{99}=\frac{337+x}{99}\;;\\
4,(x3)=\frac{400+10x+3-4}{99}=\frac{399+10x}{99}\;;[/tex]
↓
[tex]\frac{99x+34}{99}+\frac{337+x}{99}+\frac{399+10x}{99}=x+8\;\;|_{\cdot99}\\
99x+34+337+x+399+10x=99x+792\;\\
11x=22\;\;\rightarrow\;\;\fbox{x=2}[/tex]
