Răspuns:
Explicație:
SO3
M= 32 + 3.16=80-------> 80g/moli
80g SO3---------32g S--------48g o
100g-----------------x---------------y
x= 100 . 32 : 80=40% S
y= 100 . 48 : 80=60% O
H2CO3
M= 2 +12 +3 . 16 =62-------> 62g/moli
62g H2CO3---------2g H --------12gC---------48 gO
100g-----------------------x--------------y----------------z
x= 100 . 2 : 62=3,23% H
y= 100 . 12 : 62=19,35% C
z= 100 . 48 : 62 =77,42% O
