Răspuns:
AB^2+BC^2=AC^2
m(A)=90 grade
=>M(B)=M(C)=45 grade
Sinα=c.o/ip
sinc=45 grade
=>
sinc=c.o/ip
sin45=1/√2
1/√2=5/ip
1/√2*ip=5
ip=5/(1/√2)
ip=5√2
m(<A)=90°
m(<B)=m(<C)=90/2=45°
Sina=c.o/ip
Sinc=45°
Sin45=
[tex] \frac{1}{ \sqrt{2} } [/tex]
[tex] \frac{1}{ \sqrt{2} } [/tex]*ip=5
ip=
[tex]5 \sqrt{2} [/tex]
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