Dau coroana cine ma ajuta la 5.
Ajutati-ma va rog.
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Răspuns:
m∡(AOC)=m∡(AOB)+40°
m∡(AOB)=m∡(BOC)×2⇒m∡(AOC)=m∡(BOC)×2+40°
360°=m∡(BOC)+m∡(BOC)×2+m∡(BOC)×2+40°
m∡(BOC)=320°/5=64°
m∡(AOB)=64°×2=128°
m∡(AOC)=128°+40°=168°