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Baciuremus12345
a fost răspuns

a= 5√6-6√24+7√54-8√96+9√150
b=(2√3-3√12+4√27-7√3+3√75)·√2
calculati media aridmetica si media geometrica a numerelor

Răspuns :

Renatemambouko
a= 5√6-6√24+7√54-8√96+9√150=
=5√6-12√6+21√6-32√6+45√6=
=√6(5-12+21-32+45)=
=27√6


b=(2√3-3√12+4√27-7√3+3√75)·√2=
=(2√3-6√3+12√3-7√3+15√3)·√2=
=(2-6+12-7+15)√3·√2=16√6

ma=(27√6+16√6)/2=21,5√6
mg=√(27√6×16√6)=√2592=36√2

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