[tex] \frac{n!}{(n-7)!} =336- \frac{(n-3)!}{(n-7)!} \\ \\
\frac{(n-7)!(n-6)(n-5)(n-4)(n-3)(n-2)(n-1)n}{(n-7)!} =336- \frac{(n-7)!(n-6)(n-5)(n-4)(n-3)}{(n-7)!} \\ \\
(n-2)(n-1)n=336 \\ \\
n^{3} -3 n^{2} +2n-336=0[/tex]
rezolvi cu horner si afli solutiile
