Răspuns:3] M CuSo4=64+32+4.16=160g/mol Nr.moli=m/M=320/160=2moli se aplica concentratia molara Cm=Nr.moli/V V=Nr moli/Cm=2/2= 1L
4] Cm=Nr.moli/V=6/3=2M 5] Cm=Nr.moli/V Nrmoli=Cm.V=4.10=40moli dar Nr.moli=m/M m CaCO3=nrmoli.M =40 moli.100g/mol=4000g=4kg MCaCO3=40+12+3.16=100g/mol
Explicație: