MSO2=32+32=64 g/mol MSO3=80g/mol
se considera x moli de SO2 si un x mol de SO3.
masa amestecului este;
64x+80x=288 ==> x=288/144=2 moli
mSO2=2*64=128(g)
64gSO2 exista 6,023*10²³atomi de S si 2*6,023*10²³atomi de O
124g SO2 2*6,023*10²³atomi de S si 4*6,023*10²³atomi deO
mSO3=2*80=160(g)
1mol SO3 contine 6,023*10²³atomi deS si 3*6,023*10²³atomi deO
2moli SO3 2*6,023*10²³atomi deS si 6*6,023*10²³atomi deO
Numarul total: 4*6,023*10²³atomi de S si 10*6,023*10²³atomi deO
le-am adunat
DECI: 14*6,023*10²³atomi =84,322*10²³atomi
