Răspuns :
ABCD-romb
ΔABD
AM_/_BD
AM-h
AB=AD=6 ⇒ABD-echilateral ⇒AM=l√3/2= 6√3/2= 3√3
mas<60
fie CM_/_BD
CM=AM=AC/2 ⇒AC=2*AM=2*3√3=6√3
BD-diag=l=6
A=(d1*d2)/2= 6*6√3/2= 3*6√3=18√3
ΔABD
AM_/_BD
AM-h
AB=AD=6 ⇒ABD-echilateral ⇒AM=l√3/2= 6√3/2= 3√3
mas<60
fie CM_/_BD
CM=AM=AC/2 ⇒AC=2*AM=2*3√3=6√3
BD-diag=l=6
A=(d1*d2)/2= 6*6√3/2= 3*6√3=18√3