Răspuns:
c)0,003moli
Explicație:
[tex]w=\frac{m(sub)}{m(sol)} *100%[/tex]
[tex]m(sub)=\frac{w*m(sub)}{100}[/tex]
[tex]m(sub)=\frac{36.5g*0.3}{100} =0.1095g[/tex]
[tex]M(HCl)=36.5g/mol[/tex]
[tex]n=\frac{m(sub)}{M(HCl)}[/tex]
[tex]n=\frac{0.1095g}{36.5g/mol} =0.003[/tex]mol