va rog,cine poate rezolva
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[tex]\frac{\sqrt{6} }{2} +\frac{3\sqrt{6} }{2}-2\sqrt{6} =\frac{\sqrt{6} }{2} +\frac{3\sqrt{6} }{2}-\frac{4\sqrt{6} }{2} = \frac{4\sqrt{6}-4\sqrt{6} }{2} =0[/tex]
Răspuns:
0
Explicație pas cu pas:
√3/√2+3√6/2-√24=√6/2+3√6/2-2√6=1/2(√6+3√6-4√6)=0