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ajutati-ma!!
rez ecuatiile:
10-2(x-1)²=3(x-1)-(x-2)·(2x+1)
4(x-1)²+3(x+2)²=7(x-1)²-2(4-x)

Răspuns :

Madalinaaaa

10-2(x-1)²=3(x-1)-(x-2)(2x+1)⇒10-2(x²-2x+1)=3x-3-(2x²+x-4x-2)⇒10-2x²+4x-2=3x-3-2x²-x+4x+2⇒8+4x=-1+6x⇒7=2x⇒x=7/2

4(x-1)²+3(x+2)²=7(x-1)²-2(4-x)⇒4(x²-2x+1)+3(x²+4x+4)=7(x²-2x+1)-8+2x⇒4x²-8x+4+3x²+12x+12=7x²-14x+7-8+2x⇒7x²+4x+16=7x²-12x-1⇒16x=-17⇒x=-17/16

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