Răspuns: 2Mg+O2=2MgO 100g.........4g impuritati 5 g.............................................................x x=5.4/100=0,2g imp
Explicație:mMpur =5-0,2=4,8g M Mg =24 MMgO =24+16=40g
2.24gMg...............2.40gMgO 4,8gMg ............ x x=4,8.2.40/2.24=8gMgO 1mol .................40g ..........40g.......................................y.......................8g ......y=8/40=0,2moliMgO...........
