a)AC=12 dm;AD=6 dm
AB,BC,BD,CD=?
In ΔADC: CD²=AC²-AD²=144dm²-36dm²=108dm²
=> CD=√(108dm²)=6√3dm
Teorema inaltimii: AD²=BD•DC => BD=AD²/DC=36dm²/(6√3dm)
BD=6dm/√3=2√3dm
BC=BD+CD=2√3dm+6√3dm
BC=8√3dm
In ΔABC: AB²=BC²-AC²=192dm²-144dm²=48dm²
AB=√(48dm²)=4√3dm
b)BD=4 m;CD=6m
AB,AC,BC,AD=?
BC=BD+CD=4m+6m=10m
Teorema inaltimii: AD²=BD•DC=4m²•6m²=24m²
AD=√(24m²)=2√6m
In ΔABD: AB²=AD²+BD²=24m²+16m²=40m²
AB=√(40m²)=2√10m
In ΔABC: AC²=BC²-AB²=100m²-40m²=60m²
AC=√(60m²)=2√15m
