Răspuns:
-2[tex]x^{2}[/tex] -3x+5=0 D= [tex]b^{2}[/tex]- 4ac= 9- 4*(-2)*5=9+40=49
x1=(-b-[tex]\sqrt{D}[/tex])/2a= 3-7/-4= -4/-4= 1 x1=1
x2= (-b+[tex]\sqrt{D}[/tex])/2a= 3+7/-4= 8/-4= -2 x2=-2
ai grija la semne - (-2)= 2
-2 :-2=1