Răspuns:
M,Zn=65g/mol
M,ZnCl2=136g/mol
1mol.......................1mol
Zn + 2HCl------> ZnCl2 + H2
65g,,,,,,,,,,,,,,,,,,,,,,,,,,,,136g
4g..............................x= m= 8,37gZnCl2
niu= m/M= 8,37/136mol= 0,06mol-----------------------d
Explicație: