Exercitiul fara greseli acum:
Fie a,b,c ∈ Q+ si[tex] \frac{a}{2b+3c} = \frac{2b}{a+3c}= \frac{3c}{a+2b} [/tex].
Calculati valoarea expresiei (a+b+c) ([tex] \frac{1}{a}+ \frac{1}{b} + \frac{1}{c} [/tex]).