AJUTORRRRRRRRRRRRRRRRRRRRRRRRRRRRRR!!!! Determinati nr. de forma abc știind ca 2(ab+ba)+2 la puterea c=67
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Răspuns:
Explicație pas cu pas:
2*11(a+b)+2^c=67
67 impar, 2*11(a+b) par, deci 2^c impar deci c=0 2^0=1
2*11(a+b) =66
a+b=3
a, b , cifre nenule
dec i a=1, b=2 sau a=2, b=1
abc numar ∈{120, 210}