Răspuns:
sper ca te am ajutat! :*
(x+3)(4x+16-3x-15)<0
4x²+16x-3x²-15x+12x+48-9x-45<0
x²+4x+3<0
∆=16-12=4; √∆=2
x¹= (-4-2)/2=(-3)
x²=(-4+2)/2=(-1)
