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32mL= 0,032 L
2 KOH+ H2SO4 ---> K2SO4 + 2 H2O
Cm= n/V => n= Cm*V = 0,366*0,032 =0,012 moli de KOH
2 moli KOH................ 1 mol H2SO4
0,012 moli KOH........ x moli H2SO4
x= 0,012/2= 0,006 moli H2SO4
Cm= n/V => V= n/Cm = 0,006/0,366= 0,016 L= 16 mL solutie de H2SO4