Răspuns:
descompunem in baza zece
ab+ba/4a+4b
10a+b+10b+a /4a+4b
11a+11b/4a+4b
11(a+b)/4(a+b)
se simplifică parantezele
11/4
[tex]\dfrac{\overline{ab}+\overline{ba}}{4a+4b} = \dfrac{(10\cdot a+b)+(10\cdot b+a)}{4a+4b} = \dfrac{11\cdot a+11\cdot b}{4a+4b} =\\ \\ = \dfrac{11(a+b)}{4(a+b)} = \dfrac{11}{4}[/tex]
