Răspuns:
axb-axc=26 ax(b-c)=26 ax(b-c)= 13x2 => a=13 b=c+2
b=a+2 =15 c= b+2=17 (sunt impare consecutive )
a=13, b=15, c=17
sau b=a+2, c= b+2= a+4 si inlocuim in
ax(b-c)=26 ax(a+2-a-4)=26
ax(-2)=26 => a= 26:2 = 13 a=13 b= 15 c= 17
numere impare consecutive sunt de forma a=2k+1
