Răspuns:
Explicație pas cu pas:
[tex](\dfrac{3}{5})^{15}=p^{5},~vom~egala~exponentii,~~((\dfrac{3}{5})^{3})^{5}=p^{5},\\(\dfrac{27}{125})^{5}=p^{5},~deci~p=\dfrac{27}{125}.\\(\dfrac{3}{5})^{15}=q^{3},~vom~egala~exponentii,~~((\dfrac{3}{5})^{5})^{3}=q^{3},\\(\dfrac{243}{3125})^{3}=q^{3},~deci~q=\dfrac{243}{3125}.[/tex]
