Răspuns:
Explicație:
1.
400g NAOH
r. cu H2SO4
m sare =?
400g xg
2 NaOH + H2SO4= Na2SO4 +2H2O
2.40g 142g
x=400.142 : 80=710g Na2SO4
n=710g : 142g/moli=5moli Na2SO4
MNaOH=23 +16 +1=40-------> 40g/moli
MNa2SO4=2.23 +32 +4.16=142-------> 142g/moli
