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Ajutatima va rog.x+6radical din3 +2xradical din3 +3=0

Răspuns :

x+6√3+2x√3+3=0     x(1+2√3)+3(1+2√3)=0    x=-3(1+2√3)/(1+2√3)=-3

x+6√3+2x√3+3=0
x(1+2√3)=-(6√3+3)
x=-(6√3+3)/(1+2√3)      rationalizam
x=-(6√3+3)(1-2√3)/(1+2√3)(1-2√3)
x=-(6√3-36+3-6√3)/(1-12)
x=-33/11    simplificam cu 3
x=-3