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Aratati ca:
a) (2x+3)³-8x-12=(2x+1)(2x+3)(2x+5)
b) (x²+x-4)²-4=(x-1)(x-2)(x+2)(x+3)
c) (x²+5x-4)(x²+5x-8)+4=(x+6)²(x-1)²
d)(x+5)²-9x-45=(x+2)(x+5)(x+8)

Help plsss :( . :*

Răspuns :

Alesyo
[tex](2x+3)^{2} -8x-12=(2x+1)(2x+3)(2x+5) 4x^{2}+12x+9-8x-12 = 4x^{2}+4x-3 [/tex]

[tex](2x+1)(2x+3)= 4 x^{2}+6x+2x+3 = 4 x^{2} +8x +3 (2x+5)(4 x^{2} +8x +3) = 6 x^{2}+16x+6x+9 x^{2}+40x+15 = [/tex]