a)
Vs = 334 cm3, ro = 1,31 g/cm3, c% = 32%
stim ca ro = ms/Vs => ms = roxVs
= 334x1,31 = 437,54 g sol. KOH
stim ca c% = mdx100/ms
=> md = msxc%/100
= 437,54x32/100 = 140 g KOH
140 g md g
2KOH + H2SO4 --> K2SO4 +2H2O
2x56 98
=> md = 140x98/2x56
= 122,5 g H2SO4
din c% => ms = mdx100/c%
= 122,5x100/98 = 125 g sol. H2SO4
din ro => Vs = ms/ro
= 125/1,841 = 67,89 cm3 sol. H2SO4
b)
140 g m
2KOH + H2SO4 --> K2SO4 +2H2O
2x56 174
=> m = 140x174/2x56 = 217,5 g sare
c)
ms.final = m.sare + m.apa formata + m.apa sol.KOH + m.apa.solH2SO4
m.apa sol.KOH = ms.KOH - md.KOH
= 437,54 - 140 = 297,54 g
m.apa.solH2SO4 = ms.H2SO4 - md.H2SO4
= 125 - 122,5 = 2,5 g
140 g m.format
2KOH + H2SO4 --> K2SO4 +2H2O
2x56 2x18
=> m.apa.formata = 140x2x18/2x56
= 45 g
=> ms.final = 217,5 + 45 + 297,54 + 2,5
= 562,54 g
d)
md = m = 217,5 g
=> c.f% = 217,5x100/ 562,54
= 38,66%
