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Alexionutz2001
a fost răspuns

x+1 supra 8=2 supra x+1

Răspuns :

Alesyo
[tex] \frac{x+1}{8} =\frac{2}{x+1} (x+1)(x+1)= x^{2}+x+x+1= x^{2}+2x+1 x^{2}+2x+1=16 x^{2}+2x+1-16=0 x^{2}+2x-15=0 si de aici faci cu delta pt ca e ecuatie de gradul al 2 lea [/tex]

Aplici formula Δ=[tex] b^{2}-4ac a=1 b=2 c=-15 [/tex]
[tex] \frac{x+1}{8}= \frac{2}{x+1}=>(x+1)(x+1)=16=> x^{2} +x+x+1=16=> \\ x^{2} +2x+1=16=> (x+1)^{2}=16=>x+1= 4=>x=3[/tex]

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