Răspuns:
d) [tex](2\frac{1}{2}) ^{n} =\frac{125}{8}[/tex] ; [tex](\frac{5}{2}) ^{n} =(\frac{5}{2}) ^{3}[/tex] ⇒ n = 3
e) [tex](\frac{1}{3^{2}}) ^{n}=\frac{1}{729}[/tex] ; [tex](\frac{1}{9}) ^{n}=\frac{1}{9^{3} }[/tex] ⇒ n = 3
f) [tex](\frac{1}{8})^{n} = \frac{1}{4^{3}}[/tex] ; [tex](\frac{1}{2^{3}})^{n} = \frac{1}{(2^{2})^{3}}[/tex] ; [tex]\frac{1}{2^{3n}} = \frac{1}{2^{6}}[/tex] ⇒ n = 2
Explicație pas cu pas:
