Răspuns:
Explicație pas cu pas:
AB=8, AE=EB, deci EB=4. C'C=6, C'E=2√22
C'C⊥(ABC), ⇒C'C⊥CE, deci ΔC'CE dreptunghic. ⇒CE²=C'E²-C'C²=(2√22)²-6²=4·22-36=4·(22-9)=4·13,
Din ΔBCE, dereptunghic in B, ⇒BC²=CE²-BE²=4·13-4²=4·(13-4)=4·9. Deci BC=√(4·9)=2·3=6.
Aria(t)=Aria(l)+2·Aria(b).
Aria(l)=P(b)·h=2·(AB+BC)·C'C=2·(8+6)·6=2·14·6=28·6=168
Aria(b)=AB·BC=8·6=48
Deci Aria(t)=168+2·48=168+96=264.
Volum=Aria(b)·h=48·C'C=48·6=288
d(A',BC')=d(A,BC')=AB=8
