Răspuns :
x^2-10x+25=(x-5)^2
x^2-2x+1=(x-1)^2
2x^2-4x-5 = 2(x-2-[tex]\sqrt{14}[/tex])(x-2+[tex]\sqrt{14}[/tex])
3x^2-2x-5= 3(x- [tex]\frac{10}{3}[/tex])(x+2)
x^2-10x+25=(x-5)^2
x^2-2x+1=(x-1)^2
2x^2-4x-5 = 2(x-2-[tex]\sqrt{14}[/tex])(x-2+[tex]\sqrt{14}[/tex])
3x^2-2x-5= 3(x- [tex]\frac{10}{3}[/tex])(x+2)