[tex] {x}^{2} \sqrt{3} + x \sqrt{6} = x \sqrt{3} (x + \sqrt{2} )[/tex]
[tex]x {}^{5} \sqrt{12} + x {}^{3} \sqrt{8} = x {}^{3} \sqrt{4} ( {x}^{2} \sqrt{ 3} + \sqrt{2} )[/tex]
[tex] {x}^{9} + {x}^{8} = {x}^{8} (x + 1)[/tex]
[tex] {x}^{10} - {x}^{11} = {x}^{10} (1 - x)[/tex]
