👤
a fost răspuns

suma cifrelor numarului:A=2a011+20b11+20lcl+2011d-abcd este:a.5; b.5; c.16; d.14.​

Răspuns :

Lucasela

A=2a011+20b11+20lcl+2011d-abcd

A=(20011+a000)+(20011+b00)+(20101+c0)+(20110+d)-abcd

A=(20011+ 20011 +20101 +20110)+ (a000+b00+c0+d)-abcd

A=80233+abcd-abcd

A=80233

suma cifrelor=8+2+3+3=16

Alte intrebari